Biggest: Pralsetinib, Blu667, CAS 2097132-94-8, stock 115g

Apr 05, 2019
Biggest: Pralsetinib, Blu667, CAS 2097132-94-8, stock 115g

We have already carried out Pralsetinib, Blu667, CAS 2097132-94-8 batch production, also have completed the development of quality standards and process validation. The stable process is the guarantee of product quality. For Pralsetinib, Blu667, CAS 2097132-94-8 , we use HPLC-UV detection instead of other companies' HPLC-ELSD test, Our detection method is more sensitive.

Pralsetinib, Blu667, CAS 2097132-94-8, assay more than 115g, Pralsetinib, Blu667, CAS 2097132-94-8 assay more than 99%, HNMR, MASS, COA, MSDS is ok.

Description: Pralsetinib, also known as BLU-667, is a highly potent, selective, next generation RET inhibitor with IC50 of 0.3-0.4 nM for WT RET, RET mutants V804L, V804M, M918T and CCDC6-RET fusion.. BLU-667 is a potent and selective inhibitor of RET mutations, fusions, and predicted resistant mutants. RET fusions are key drivers of multiple cancers, including lung and thyroid cancer, and our research suggests that RET also plays a key role in some colon and breast cancers. By simultaneously targeting the primary driver and predicted resistant mutants that render cancer cells insensitive to treatment with currently approved drugs.

Name: Pralsetinib free base 
CAS#: 2097132-94-8 (free base) 
Chemical Formula: C27H32FN9O2 
Exact Mass: 533.2663 
Molecular Weight: 533.6124 
Elemental Analysis: C, 60.77; H, 6.04; F, 3.56; N, 23.62; O, 6.00

Related CAS #: 2097132-94-8 (free base)   2097132-93-7 (trans-isomer)    
Synonym: Pralsetinib; BLU-667; BLU 667; BLU667;
IUPAC/Chemical Name: cis-N-{(1S)-1-[6-(4-fluoro-1H-pyrazol-1-yl)pyridin-3-yl]ethyl}-1-methoxy-4-{4-methyl-6-[(5-methyl-1H-pyrazol-3-yl)amino]pyrimidin-2-yl}cyclohexane-1-carboxamide
InChi Code: InChI=1S/C27H32FN9O2/c1-16-11-23(33-25(32-16)19-7-9-27(39-4,10-8-19)26(29)38)37(24-12-17(2)34-35-24)18(3)20-5-6-22(30-13-20)36-15-21(28)14-31-36/h5-6,11-15,18-19H,7-10H2,1-4H3,(H2,29,38)(H,34,35)/t18-,19-,27+/m0/s1
SMILES Code: O=C([C@@]1(OC)CC[C@@H](C2=NC(NC3=NNC(C)=C3)=CC(C)=N2)CC1)N[C@H](C4=CC=C(N5N=CC(F)=C5)N=C4)C