The use of CadrofloxacinHydrochloride in the treatment

Nov 26, 2018
1.CadrofloxacinHydrochloride and intermediates
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 28749-88-4
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 116751-24-7
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-84-6
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-86-8
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-91-5
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-92-6
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-93-7
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-94-8
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128426-95-9
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 153808-81-2
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 74879-18-8
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 1115-59-9
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 128427-04-3
CadrofloxacinHydrochloride 128427-55-4;153808-85-6(free)  intermediate: 78551-38-9

2.ROS-CadrofloxacinHydrochloride


3.
Name: Cadrofloxacin
CAS#: 128427-55-4;153808-85-6(free)
Chemical Formula: C19H20F3N3O4
Exact Mass: 411.1406
Molecular Weight: 411.3812
Elemental Analysis: C, 55.47; H, 4.90; F, 13.85; N, 10.21; O, 15.56

Synonym: CS-940; CS 940; CS940; Cadrofloxacin; Caderofloxacin; Cadrofloxacin hydrochloride; Cadrofloxacin HCl.

IUPAC/Chemical Name: (S)-1-cyclopropyl-8-(difluoromethoxy)-6-fluoro-7-(3-methylpiperazin-1-yl)-4-oxo-1,4-dihydroquinoline-3-carboxylic acid

InChi Key: QBDBUKJBJJWZMG-VIFPVBQESA-N

InChi Code: InChI=1S/C19H20F3N3O4/c1-9-7-24(5-4-23-9)15-13(20)6-11-14(17(15)29-19(21)22)25(10-2-3-10)8-12(16(11)26)18(27)28/h6,8-10,19,23H,2-5,7H2,1H3,(H,27,28)/t9-/m0/s1

SMILES Code: O=C(C1=CN(C2CC2)C3=C(C=C(F)C(N4C[C@H](C)NCC4)=C3OC(F)F)C1=O)O

 


 
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